2x^2-11x-16=0

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Solution for 2x^2-11x-16=0 equation:



2x^2-11x-16=0
a = 2; b = -11; c = -16;
Δ = b2-4ac
Δ = -112-4·2·(-16)
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{249}}{2*2}=\frac{11-\sqrt{249}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{249}}{2*2}=\frac{11+\sqrt{249}}{4} $

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